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<p>&nbsp;<p>
<hr noshade size="5">
<h2><a name="ThueEval"></a>
ThueEval
</h2>

missing shortdoc

<p><p>

<h3>
Syntax:
</h3>
<pre>a := ThueEval(t,x,y);</pre>

<p>

<table>
<tr>
<td>int</td>
<td><pre>  a  </pre></td>
<td></td>
</tr>
<tr>
<td>Thue object</td>
<td><pre>  t  </pre></td>
<td></td>
</tr>
<tr>
<td>int</td>
<td><pre>  x  </pre></td>
<td></td>
</tr>
<tr>
<td>int</td>
<td><pre>  y  </pre></td>
<td></td>
</tr>
</table>

<p>


See also:&nbsp;&nbsp;<a href="kashref.html#Thue">Thue</a>, <a href="kashref.html#ThueSolve">ThueSolve</a>

<p>

<h3>
Description:
</h3>
Let f(X,Y) \in {Z}[X,Y] be the homogeneous polynomial
of the <sf> Thue</sf> object <sf> t</sf> generated by the <sf> KASH</sf> function
<tt> Thue</tt>. The <tt> ThueEval</tt> function evaluates f at (x,y).

<p><p>

<p>
<hr>
<p>
<h3>
Example:
</h3>
With f(X,Y) = X^3 + X^2 Y - 6 X Y^2 + 2 Y^3 compute
f(1,1), f(3,1) and f(-724,-411). 
<pre>

kash> t := Thue([1,1,-6,2]);
X^3 + X^2 Y - 6 X Y^2 + 2 Y^3
kash> ThueEval(t,1,1);
-2
kash> ThueEval(t,3,1);
20
kash> ThueEval(t,-724,-411);
> 2

</pre>

<p>


<hr>

<p>
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